Over at Plus Magazine, I came up with a predicted medal tally for the London 2012 Olympics. Check out my Mapping the medals article if you are interested in the maths behind it.
My top 20 predicted countries (ordered by total number of medals) are:
| 2012 Predicted Position | 2012 Predicted Medals | |
| United States | 1 | 112 |
| Great Britain | 2 | 79 |
| Russia | 3 | 77 |
| China | 4 | 76 |
| Australia | 5 | 53 |
| France | 6 | 42 |
| Germany | 6 | 42 |
| South Korea | 8 | 32 |
| Ukraine | 9 | 29 |
| Italy | 10 | 28 |
| Japan | 11 | 25 |
| Cuba | 12 | 25 |
| Belarus | 13 | 21 |
| Canada | 14 | 19 |
| Spain | 14 | 19 |
| Netherlands | 16 | 17 |
| Brazil | 17 | 16 |
| Kenya | 18 | 15 |
| Kazakhstan | 18 | 15 |
| Jamaica | 20 | 12 |
And check out my interactive world map, where my predicted top 20 countries are coloured. If you click on each country, you will see results from previous games, a (semi-regularly) updated 2012 medal count, and some occasional comments.


of the drag force acting on a swimmer moving in a fluid is given by the following equation![\[ F_ D=\frac{1}{2}\rho v^2 C_ D A, \]](http://plus.maths.org/MI/1090f42a51914e0ebd03b208305002ac/images/img-0002.png)
is the mass density of the fluid
is the speed of the swimmer relative to the fluid
is the swimmer's cross-sectional area, that is the area of your body as it is pushing through the water head on
is the drag-coefficient,
a number which depends on factors such as the exact shape of the
swimmer and the hydrodynamic qualities of their skin and what they are
wearing.
is
the rate at which your body uses its energy, and when you are swimming
the power you exert is proportional to the cube of your speed 
![\[ P=F_ D v = \frac{1}{2}\rho C_ D A v^3. \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0003.png)
. To do this solely by increasing your power, you need to exert a new power 
![\[ P_1 = \frac{1}{2}\rho C_ D A (v+0.1v)^3. \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0006.png)
![\[ Increase = 100 \times \frac{P_1-P}{P}= 100 \times (\frac{P_1}{P}-1). \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0007.png)
![\[ \frac{P_1}{P} = \frac{\frac{1}{2}\rho C_ D A (v+0.1v)^3}{\frac{1}{2}\rho C_ D A v^3}=(1.1)^3=1.331 \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0008.png)
![\[ Increase =100 \times (1.331-1)\% =33.1\% . \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0009.png)
is![\[ C_ D=\frac{2P}{\rho A v^3}. \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0011.png)
of![\[ C_{D1}=\frac{2P}{\rho A (v+0.1v)^3}. \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0013.png)
![\[ Decrease = 100 \times \frac{C_ D-C_{D1}}{C_ D}=100 \times (1-\frac{C_{D1}}{C_ D}) = 100 \times (1-\frac{1}{1.1^3})= 25\% . \]](http://plus.maths.org/MI/caa263a0adba65e63c48c3c9203b58b5/images/img-0014.png)

